本文介紹了SQL Server中層次結構的動態扁平化的處理方法，對大家解決問題具有一定的參考價值，需要的朋友們下面隨著小編來一起學習吧！
問題描述
我們有一個表LedgerAccount，其父子關系類似于：
CREATE TABLE [dbo].[LedgerAccounts](
[ledger_key] [int] NOT NULL,
[Ledger] [nvarchar](12) NULL,
[LedgerLevel] [int] NULL,
[ParentAccount] [nvarchar](12) NULL,
[LedgerDescription] [nvarchar](30) NULL,
CONSTRAINT [PK_LedgerAccount] PRIMARY KEY CLUSTERED
(
[ledger_key] ASC
)WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY]
INSERT INTO [dbo].[LedgerAccounts]
VALUES (40, '020000', 0, '020999', 'Participation'),
(41, '020999', 20, '021000', 'Participation in Group'),
(42, '021000', 0, '021999', 'Loans to..'),
(43, '021999', 20, '022000', 'Loans to group company'),
(44, '022000', 0, '022999', 'Participation in'),
(45, '022999', 20, '029999', 'Other Participation'),
(46, '029999', 30, '059999', 'Financial Fixed Assets'),
(47, '059999', 50, 'TOT.BALANS', 'Fixed Assets'),
(48, 'TOT.BALANS', 90, 'TOT.GB', 'Total Balance sheet'),
(49, 'TOT.GB', 99, 'NULL', 'Total GL')
LedgerLevel定義層次結構中的級別。父節點059999位于最高級別(在本例中為90)，并且0是最低級別的子節點。
我需要使用上表中的層次關系創建一個表/結構/tmp.table，如下所示：
在這里，我們可以對級別的數量和級別ID進行參數化。
以下是我嘗試過的查詢，沒有考慮參數化，并假定級別數=4。
如何才能在不硬編碼級別數量和級別ID的情況下實現相同的目標？
我是一個SQL新手，對它有基本的了解。
create or alter view [dbo].[Ledgerview] as
WITH LedgerAccountstree AS
(
SELECT
ledger_key,
Ledger as CurrLedgerCode,
Ledger,
Ledger as Lvl0Code,
LedgerDescription as Lvl0Description,
cast('-' as nvarchar(12)) as Lvl1Code,
cast('-' as nvarchar(30)) as Lvl1Description,
cast('-' as nvarchar(12)) as Lvl2Code,
cast('-' as nvarchar(30)) as Lvl2Description,
cast('-' as nvarchar(12)) as Lvl3Code,
cast('-' as nvarchar(30)) as Lvl3Description,
ParentAccount,
LedgerLevel
FROM
[dbo].[LedgerAccounts]
WHERE
LedgerLevel = 50
UNION ALL
SELECT
[dbo].[LedgerAccounts].ledger_key,
LedgerAccountstree.CurrLedgerCode,
[dbo].[LedgerAccounts].Ledger,
LedgerAccountstree.Lvl0Code,
LedgerAccountstree.Lvl0Description,
case when [dbo].[LedgerAccounts].LedgerLevel = 30 then [dbo].[LedgerAccounts].Ledger else LedgerAccountstree.Lvl1Code end as Lvl1Code,
case when [dbo].[LedgerAccounts].LedgerLevel = 30 then [dbo].[LedgerAccounts].LedgerDescription else LedgerAccountstree.Lvl1Description end as Lvl1Description,
case when [dbo].[LedgerAccounts].LedgerLevel = 20 then [dbo].[LedgerAccounts].Ledger else LedgerAccountstree.Lvl2Code end as Lvl2Code,
case when [dbo].[LedgerAccounts].LedgerLevel = 20 then [dbo].[LedgerAccounts].LedgerDescription else LedgerAccountstree.Lvl2Description end as Lvl2Description,
case when [dbo].[LedgerAccounts].LedgerLevel = 0 then [dbo].[LedgerAccounts].Ledger else LedgerAccountstree.Lvl3Code end as Lvl3Code,
case when [dbo].[LedgerAccounts].LedgerLevel = 0 then [dbo].[LedgerAccounts].LedgerDescription else LedgerAccountstree.Lvl3Description end as Lvl3Description,
[dbo].[LedgerAccounts].ParentAccount,
[dbo].[LedgerAccounts].LedgerLevel
FROM
[dbo].[LedgerAccounts]
JOIN
LedgerAccountstree
ON LedgerAccountstree.Ledger = [dbo].[LedgerAccounts].[ParentAccount]
)
SELECT
ledger_key,
Ledger,
Lvl0Code +'-'+ Lvl0Description as Level0,
Lvl1Code +'-'+ Lvl1Description as Level1,
Lvl2Code +'-'+ Lvl2Description as Level2,
Lvl3Code +'-'+ Lvl3Description as Level3
FROM
LedgerAccountstree
轉到
推薦答案
這應該可以滿足您的要求。
這里發生了很多事情，試圖將其分解成微小的細節將很快成為TLDR。因此，如果你有關于我為什么做某事或某事如何工作的具體問題，請在評論中提問，我會更新答案，包括那些具體的細節。
USE tempdb;
GO
IF OBJECT_ID('tempdb.dbo.LedgerAccounts', 'U') IS NOT NULL
BEGIN DROP TABLE tempdb.dbo.LedgerAccounts; END;
GO
CREATE TABLE tempdb.dbo.LedgerAccounts (
ledger_key int NOT NULL,
Ledger nvarchar (12) NULL,
LedgerLevel int NULL,
ParentAccount nvarchar (12) NULL,
LedgerDescription nvarchar (30) NULL,
CONSTRAINT PK_LedgerAccount
PRIMARY KEY CLUSTERED (ledger_key ASC)
WITH (PAD_INDEX = OFF, STATISTICS_NORECOMPUTE = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS = ON, ALLOW_PAGE_LOCKS = ON) ON [PRIMARY]
) ON [PRIMARY];
GO
INSERT INTO tempdb.dbo.LedgerAccounts
VALUES (40, '020000', 0, '020999', 'Participation'),
(41, '020999', 20, '021000', 'Participation in Group'),
(42, '021000', 0, '021999', 'Loans to..'),
(43, '021999', 20, '022000', 'Loans to group company'),
(44, '022000', 0, '022999', 'Participation in'),
(45, '022999', 20, '029999', 'Other Participation'),
(46, '029999', 30, '059999', 'Financial Fixed Assets'),
(47, '059999', 50, 'TOT.BALANS', 'Fixed Assets'),
(48, 'TOT.BALANS', 90, 'TOT.GB', 'Total Balance sheet'),
(49, 'TOT.GB', 99, 'NULL', 'Total GL');
GO
-- SELECT * FROM tempdb.dbo.LedgerAccounts la;
--=====================================================================================================================
--=====================================================================================================================
IF OBJECT_ID('tempdb..#build_path', 'U') IS NOT NULL
BEGIN DROP TABLE #build_path; END;
GO
CREATE TABLE #build_path (
ledger_key int NOT NULL,
Ledger nvarchar(12) NOT NULL,
ParentAccount nvarchar(30) NOT NULL,
h_level int NOT NULL,
h_path nvarchar(4000) NOT NULL
);
GO
WITH
cte_build_path AS (
SELECT
la.ledger_key,
la.Ledger,
la.ParentAccount,
h_level = 0,
h_path = CONVERT(nvarchar(4000), RIGHT(REPLICATE(N' ', 50) + la.ledger + N'-' + la.LedgerDescription, 50))
FROM
dbo.LedgerAccounts la
WHERE
la.Ledger LIKE '[0-9][0-9][0-9][0-9][0-9][0-9]'
AND la.ParentAccount NOT LIKE '[0-9][0-9][0-9][0-9][0-9][0-9]'
UNION ALL
SELECT
la.ledger_key,
la.Ledger,
la.ParentAccount,
h_level = bp.h_level + 1,
h_path = CONVERT(nvarchar(4000), bp.h_path + RIGHT(REPLICATE(N' ', 50) + la.ledger + N'-' + la.LedgerDescription, 50))
FROM
dbo.LedgerAccounts la
JOIN cte_build_path bp
ON la.ParentAccount = bp.Ledger
)
INSERT #build_path (ledger_key, Ledger, ParentAccount, h_level, h_path)
SELECT
bp .ledger_key,
bp.Ledger,
bp.ParentAccount,
bp.h_level,
bp.h_path
FROM
cte_build_path bp;
GO
-- SELECT * FROM #build_path bp
--=====================================================================================================================
DECLARE
@d_col_count int = (SELECT MAX(bp.h_level) FROM #build_path bp) + 1,
@d_sql nvarchar(MAX) = N'',
@debug bit = 0;
SELECT TOP (@d_col_count)
@d_sql = CONCAT(@d_sql, N',
[level', x.rn, N'] = CASE WHEN bp.h_level >= ', x.rn, N' THEN LTRIM(SUBSTRING(bp.h_path, ', x.rn * 50 + 1, N', 50)) ELSE N''---'' END'
)
FROM
(
SELECT TOP (@d_col_count)
rn = ROW_NUMBER() OVER (ORDER BY ac.object_id) - 1
FROM
sys.all_columns ac
) x
ORDER BY
x.rn ASC;
SELECT @d_sql = CONCAT(N'
SELECT
bp.ledger_key,
bp.Ledger',
@d_sql, N'
FROM
#build_path bp;');
IF @debug = 1
BEGIN
PRINT(@d_sql);
END;
ELSE
BEGIN
EXEC sys.sp_executesql @d_sql
END;
GO
和結果…
ledger_key Ledger level0 level1 level2 level3 level4 level5 level6 level7
----------- ------------ -------------------------------------------------- -------------------------------------------------- -------------------------------------------------- -------------------------------------------------- -------------------------------------------------- -------------------------------------------------- -------------------------------------------------- --------------------------------------------------
47 059999 059999-Fixed Assets --- --- --- --- --- --- ---
46 029999 059999-Fixed Assets 029999-Financial Fixed Assets --- --- --- --- --- ---
45 022999 059999-Fixed Assets 029999-Financial Fixed Assets 022999-Other Participation --- --- --- --- ---
44 022000 059999-Fixed Assets 029999-Financial Fixed Assets 022999-Other Participation 022000-Participation in --- --- --- ---
43 021999 059999-Fixed Assets 029999-Financial Fixed Assets 022999-Other Participation 022000-Participation in 021999-Loans to group company --- --- ---
42 021000 059999-Fixed Assets 029999-Financial Fixed Assets 022999-Other Participation 022000-Participation in 021999-Loans to group company 021000-Loans to.. --- ---
41 020999 059999-Fixed Assets 029999-Financial Fixed Assets 022999-Other Participation 022000-Participation in 021999-Loans to group company 021000-Loans to.. 020999-Participation in Group ---
40 020000 059999-Fixed Assets 029999-Financial Fixed Assets 022999-Other Participation 022000-Participation in 021999-Loans to group company 021000-Loans to.. 020999-Participation in Group 020000-Participation
這篇關于SQL Server中層次結構的動態扁平化的文章就介紹到這了，希望我們推薦的答案對大家有所幫助，
